Using a suitable identity- we can find out that 2 y -52 y -5 is equal to A- 4 y 2-10 y -25B- 4 y2-20 y-25C- 4 y 2-20 y -15

The correct option is B 4y^2+20y+25We know that, (a+b)×(a+b)=(a+b)^2 Using the identity (a+b)^2=a^2+2ab+b^2, (2y+5)(2y+5) = (2y +5)^2 = (2y)^2 + 2(2y) (5) + 5 ...

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Standard VIII

Mathematics

Algebraic Quadratic Identity

Using a suita...

Question

Using a suitable identity, we can find out that $(2 y + 5) (2 y + 5)$ is equal to

4 y^{2} + 10 y + 25

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4 y^{2} + 20 y + 25

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4 y^{2} + 20 y + 15

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Solution

The correct option is B $4 y^{2} + 20 y + 25$
We know that,
$(a + b) \times (a + b) = (a + b)^{2}$

Using the identity
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ,

$(2 y + 5) (2 y + 5) = (2 y + 5)^{2}$
$= (2 y)^{2} + 2 (2 y) (5) + 5^{2}$
$= 4 y^{2} + 20 y + 25$

Suggest Corrections

Using a suitable identity, we can find out that (2y+5)(2y+5) is equal to

The correct option is B 4y2+20y+25We know that, (a+b)×(a+b)=(a+b)2 Using the identity (a+b)2=a2+2ab+b2, (2y+5)(2y+5)=(2y+5)2 =(2y)2+2(2y)(5)+52 =4y2+20y+25

Using a suitable identity, we can find out that $(2 y + 5) (2 y + 5)$ is equal to

The correct option is B $4 y^{2} + 20 y + 25$
We know that,
$(a + b) \times (a + b) = (a + b)^{2}$

Using the identity
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ,

$(2 y + 5) (2 y + 5) = (2 y + 5)^{2}$
$= (2 y)^{2} + 2 (2 y) (5) + 5^{2}$
$= 4 y^{2} + 20 y + 25$