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Question

Using algebraic identities find the coefficients of x2 term, x term and constant term.

(x+7)(x+3)(x+9)

A
19,111,189
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B
19,111,189
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C
19,111,189
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D
None of these
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Solution

The correct option is A 19,111,189
We solve the given expression (x+7)(x+3)(x+9) as shown below:

[(x+7)(x+3)](x+9)

=[x(x+3)+7(x+3)](x+9)

=(x2+3x+7x+21)(x+9)

=(x2+10x+21)(x+9)(Combiningliketerms)

=(x+9)(x2+10x+21)

=x(x2+10x+21)+9(x2+10x+21)

=x3+10x2+21x+9x2+90x+189

=x3+(10+9)x2+(21+90)x+189(Combiningliketerms)

=x3+19x2+111x+189

From the above calculation, we observe that the coefficient of x2 is 19, the coefficient of x is 111 and the constant term is 189.

Hence, the coefficient of x2 is 19, the coefficient of x is 111 and the constant term is 189..

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