Using an AC voltmeter the potential difference in an electrical line in a house is read to be 224 V if the line frequency is known to be 50 Hz. The equation of the voltage is
A
V=317 sin(50πt)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
V=317 sin(100πt)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
V=224 sin(100πt)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
V=224 sin(200πt)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A V=317 sin(100πt) Given: Voltmeter=224V ; frequency =50Hz