Using an identity expand : (2y+5)(2y+5)
4y2+10y+25
4y2+20y+25
4y2+20y+15
y2+20y+25
We know that, (a+b)×(a+b)=(a+b)2 Using the identity (a+b)2=a2+2ab+b2, (2y+5)(2y+5)=(2y+5)2 =(2y)2+2(2y)(5)+52 =4y2+20y+25
Evaluate: (2y+5)(2y+5)
Factorise: 4y2+20y+25