Using an identity expand nbsp- -2y-5-2y-5-4y-2-10y-25-4y-2-20y-25-4y-2-20y-15-y-2-20y-25-

The correct option is B 4y^2+20y+25 We know that, (a+b)×(a+b)=(a+b)^2 Using the identity (a+b)^2=a^2+2ab+b^2, (2y+5)(2y+5) = (2y +5)^2 = (2y)^2 + 2(2y) (5) + ...

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Byju's Answer

Standard VII

Mathematics

(a + b)^2 = a^2 + 2ab +b^2

Using an iden...

Question

Using an identity expand :
$(2 y + 5) (2 y + 5)$

$4 y^{2} + 10 y + 25$

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$4 y^{2} + 20 y + 25$

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$4 y^{2} + 20 y + 15$

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$y^{2} + 20 y + 25$

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Solution

The correct option is B
$4 y^{2} + 20 y + 25$

We know that,
$(a + b) \times (a + b) = (a + b)^{2}$

Using the identity
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ,

$(2 y + 5) (2 y + 5) = (2 y + 5)^{2}$
$= (2 y)^{2} + 2 (2 y) (5) + 5^{2}$
$= 4 y^{2} + 20 y + 25$

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Similar questions

Q. Solve

\frac{16 y^{2} - 20 y + 9}{8 y^{2} + 12 y + 21} = \frac{4 y - 5}{2 y + 3}

Factorise:
$4 y^{2} + 20 y + 25$

Using an identity expand :
$(2 y + 5) (2 y + 5)$

Q. Using a suitable identity, we can find out that

(2 y + 5) (2 y + 5)

is equal to

Evaluate: $(2 y + 5) (2 y + 5)$

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Using an identity expand : (2y+5)(2y+5)

The correct option is B 4y2+20y+25 We know that, (a+b)×(a+b)=(a+b)2 Using the identity (a+b)2=a2+2ab+b2, (2y+5)(2y+5)=(2y+5)2 =(2y)2+2(2y)(5)+52 =4y2+20y+25

Using an identity expand :
$(2 y + 5) (2 y + 5)$

The correct option is B
$4 y^{2} + 20 y + 25$

We know that,
$(a + b) \times (a + b) = (a + b)^{2}$

Using the identity
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ,

$(2 y + 5) (2 y + 5) = (2 y + 5)^{2}$
$= (2 y)^{2} + 2 (2 y) (5) + 5^{2}$
$= 4 y^{2} + 20 y + 25$