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Question

Using binomial theorem, write down the expansions of the following:
(1+2x3x2)5

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Solution

(1+2x3x2)5

=[(1+3x)(1x)]5

=(1+3x)5(1x)5

=[1+5(3x)+10(3x)2+10(3x)3+5(3x)4+(3x)5][15x+10x210x3+5x4x5]

=[1+15x+90x2+270x3+405x4+243x5][15x+10x210x3+5x4x5]

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