Question

Using Bohr's formula for energy quantization, the ionisation potential of the ground state of $L{i}^{++}$ atoms is:

• A. $122V$
• B. $13.6V$
• C. $3.4V$
• D. $10.2V$

Answer 1

The correct option is A $122V$

Bohr’s formula for ionization potential is given by:

$E=\frac{m{Z}^2{e}^4}{32{\pi }^2{\epsilon }_0^2{h}^2}$

Where, Z is atomic number = 3

So, $E_{\infty }-E_1=122eV$