Question

Using Bohr's theory, the transition, so that the electron's de-Broglie wavelength becomes 3 times of its original value in $H{e}^{+}$ion will be:

• A. $2\to 6$
• B. $2\to 4$
• C. $1\to 4$
• D. $1\to 6$

Answer 1

Answer: (A)

$2\to 6$

$\lambda =\frac{h}{p}=\frac{h}{mv}$
Wavelength is inversely proportional to v.So, inversely proportional to $\frac{z}{n}$.
Hence for the wavelength to become 3 times, n has to become 3 times.
So, $2\to 6.$