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Question

Using cofactors of elements of second row, evaluate Δ=∣ ∣538201123∣ ∣

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Solution

=∣ ∣538201123∣ ∣

Cofactors of elements of second row are

C21=(1)2+13823

C21=(7)=7

C22=(1)2+25813

C22=158=7

C23=(1)2+35312

C23=103=7

Now, Δ=2C21+0C22+1C23

Δ=2(7)+0(7)+1(7)=21

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