Using -6- 2-449- calculate -2-3-3-2 correct to three decimals-

≈ 2.449 ∴ is approximately equal to 2. 041. nbsp; ...

333

You visited us 333 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Decimal Expansion of Rational and Irrational Numbers

Using √6≈ 2.4...

Question

Using correct to three decimals.

Open in App

Solution

≈ 2.449

∴ is approximately equal to 2. 041.

Suggest Corrections

Similar questions

Given , $\sqrt{2} = 1.414, \sqrt{3} = 1.732$ and $\sqrt{6} = 2.449$ , find the value of $\frac{1}{\sqrt{3} - \sqrt{2} - 1}$ correct to 3 place of decimal

Given, $\sqrt{2} = 1.4141 a n d \sqrt{6} = 2.449, f i n d t h e v a l u e o f \frac{1}{\sqrt{3} - \sqrt{2} - 1}$ correct to 3 places of decimal.

Q. Given,

\sqrt{2} = 1.414 and \sqrt{6} = 2.449

, find the value of

\frac{1}{\sqrt{3} - \sqrt{2} - 1}

correct to 3 places of decimal.

Using correct to three decimals.

Find the values of each of the following correct to three places of decimals, it being given that $\sqrt{2} = 1.4142, \sqrt{3} = 1.732, \sqrt{5} = 2.2360, \sqrt{6} = 2.4492 a n d \sqrt{10} = 3.162$ .

(i) $\frac{3 - \sqrt{5}}{3 + 2 \sqrt{5}}$

(ii) $\frac{1 + \sqrt{2}}{3 - 2 \sqrt{2}}$

Join BYJU'S Learning Program