The correct option is D x = 1, y = 2, z = 3
D=⎛⎜⎝1111−1132−4∣∣
∣∣Applying C2→C2−C1, C3→C3−C1=⎛⎜⎝1001−203−1−7∣∣
∣∣=14D1=⎛⎜⎝6112−11−52−4∣∣
∣∣Applying R2→R2−R1, R3→R3+4R1=⎛⎜⎝611−4−201960∣∣
∣∣=14D2=⎛⎜⎝1611213−5−4∣∣
∣∣Applying R2→R2−R1=⎛⎜⎝1610−403−5−4∣∣
∣∣=28D3=⎛⎜⎝1161−1232−5∣∣
∣∣Applying C2→C2−C1, C3→C3−3C1=⎛⎜⎝1160−2−40−1−23∣∣
∣∣=42Hence by cramer's rule:x=D1D=1414=1y=D2D=2814=2z=D3D=4214=3