wiz-icon
MyQuestionIcon
MyQuestionIcon
13
You visited us 13 times! Enjoying our articles? Unlock Full Access!
Question

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following
(a) [CoF6]3,[Co(H2O)6]2+,[Co(CN)6]3
(b) FeF36,[Fe(H2O)6]2+,[Fe(CN)6]4

Open in App
Solution

(a) [CoF6]3,[Co(H2O)6]2+,[Co(CN)6]3

[CoF6]3
F is a weak field ligand.



Configuration of Co3+=3d6(or t42g e2g)
Number of unpaired electrons (n)=4
Magnetic moment (μ)=n(n+2)=4(4+2)=24=4.9BM [Co(H2O)6]2+

[Co(H2O)6]2+

H2O is a weak field ligand.


Configuartion of Co2+=3d7(or t52g e2g)
Number of unpaired electrons (n)=3
μ=3(3+2)=15=3.87BM

[Co(CN)6]3 i.e., Co3+
CN is strong field ligand.



Co3+=3d6(or t62g t0g)
There is no unpaired electron, so it is diamagnetic.
μ=0

(b) FeF36,[Fe(H2O)6]2+,[Fe(CN)6]4

[FeF6]3,



Number of unpaired electrons, n=5
μ=5(5+2) =35=5.92BM

[Fe(H2O)6]2+

[Fe(CN)6]4


Since, CN is a strong field ligand, all the electrons get paired.
Fe2+=3d6(or t62ge0g)
Because there is no unpaired electron, so it is diamagnetic in nature.




flag
Suggest Corrections
thumbs-up
17
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Octahedral Complexes
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon