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Question

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following
(a) [CoF6]3,[Co(H2O)6]2+,[Co(CN)6]3
(b) FeF36,[Fe(H2O)6]2+,[Fe(CN)6]4

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Solution

(a) [CoF6]3,[Co(H2O)6]2+,[Co(CN)6]3

[CoF6]3
F is a weak field ligand.



Configuration of Co3+=3d6(or t42g e2g)
Number of unpaired electrons (n)=4
Magnetic moment (μ)=n(n+2)=4(4+2)=24=4.9BM [Co(H2O)6]2+

[Co(H2O)6]2+

H2O is a weak field ligand.


Configuartion of Co2+=3d7(or t52g e2g)
Number of unpaired electrons (n)=3
μ=3(3+2)=15=3.87BM

[Co(CN)6]3 i.e., Co3+
CN is strong field ligand.



Co3+=3d6(or t62g t0g)
There is no unpaired electron, so it is diamagnetic.
μ=0

(b) FeF36,[Fe(H2O)6]2+,[Fe(CN)6]4

[FeF6]3,



Number of unpaired electrons, n=5
μ=5(5+2) =35=5.92BM

[Fe(H2O)6]2+

[Fe(CN)6]4


Since, CN is a strong field ligand, all the electrons get paired.
Fe2+=3d6(or t62ge0g)
Because there is no unpaired electron, so it is diamagnetic in nature.




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