Given, f(x)=6x3+13x2+x−2
and g(x) = 2x + 1,
f(x)÷g(x)⇒2x+1)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯6x3+13x2+x−2(3x2+5x−2
6x3+3x2
− −
–––––––––––––––––––––
10x2+x−2
10x2+5x
− −
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
−4x−2
−4x−2
+ +
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
0
quotient =3x2+5x−2, remainder = 0