Question

Using elementary row transformation find the inverse of the matrix A = $\left[\begin{array}{ccc}3& -1& -2\\ 2& 0& -1\\ 3& -5& 0\end{array}\right]$

• A. $\left[\begin{array}{ccc}\frac{-5}{8}& \frac{5}{4}& \frac{1}{8}\\ \frac{-3}{8}& \frac{3}{4}& \frac{-1}{8}\\ \frac{-5}{4}& \frac{3}{2}& \frac{1}{4}\end{array}\right]$
• B. $\frac{1}{8}\left[\begin{array}{ccc}5& -5& 1\\ 3& -3& 1\\ 0& 3& 1\end{array}\right]$
• C. $\frac{1}{8}\left[\begin{array}{ccc}5& 5& 1\\ 3& 6& -1\\ 10& -12& 2\end{array}\right]$
• D. None of these

Answer 1

The correct option is A $\left[\begin{array}{ccc}\frac{-5}{8}& \frac{5}{4}& \frac{1}{8}\\ \frac{-3}{8}& \frac{3}{4}& \frac{-1}{8}\\ \frac{-5}{4}& \frac{3}{2}& \frac{1}{4}\end{array}\right]$