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Question

Using elementary transformation find inverse of each of the followingA=[2357]

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Solution

A=[2357]
In order to find inverse by using row elementary transformation we write as A=IA.
[2357]=[1001]A

Apply R112×R1
13257=12001A

Apply R2R25R1
⎢ ⎢132012⎥ ⎥=⎢ ⎢120521⎥ ⎥A

Apply R22×R2
13201=12052A

Apply R1R132R2
[1001]=[7352]A

A1=[7352]


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