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Question

Using elementary transformations, find the inverse of matrix [2142], if it exists.


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Solution

Let A=[2142]
We know that A=IA
[2142]=[1001]A
Applying R1R112R2
212(4)112(2)42=112(0)012(1)01A
[221142]=11201A
[0042]=11201A
Since we have all zeros in the first row of the left hand side matrix of the above equation.
Therefore, A1 does not exist.

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