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Question

Using elementary transformations, find the inverse of matrix [2174], if it exists.


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Solution

Let A=[2174]
We know that A=IA
[2174]=[1001]A
Applying R1R117R2
217(7)117(4)74=117(0)017(1)01A
2114774=101701A
Applying R2R27R1
⎢ ⎢ ⎢13777(1)47(37)⎥ ⎥ ⎥=⎢ ⎢ ⎢11707(1)17(17)⎥ ⎥ ⎥A
1377743=117071+1A
13701=11772A
Applying R1R137R2
137(0)3737(1)01=137(7)1737(2)72A
10373701=1+3176772A
[1001]=[4172]A
I=[4172]A
This is similar to I=A1A
Thus, A1=[4172]

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