Using elementary transformations, find the inverse of the followng matrix.
[2142]
Let A=[2142]. We know that A =IA
∴[2142]=[1001]A⇒[11244]=[12001]A (Using R1→12R1)
⇒[11200]=[120−21]A (Using R2→R2−4R1)
Now, in the above equation, we can see all the elements are zero in the second row of the matrix on the LHS. Therefore, A−1 does not exist.