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Question

Using elementary transformations, find the inverse of the matrix [31027]

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Solution

A=[31027]

We know that A=IA (using row operations)
[31027]=[1001]A

Using operation R1R1R2
[1327]=[1101]A

Using operation R2R22R1
[1301]=[1123]A

Using operation R1R13R2
[1001]=[71023]A

Therefore,
A1=[71023]

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