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Question

Using Euclids division algorithm, find the largest number that divides 1251,9377 and 15628 leaving remainders 1,2 and 3, respectively.

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Solution

We have to find the H.C.F. of (12511=1250),(93772=9375),(156283=15625),

Find H.C.F of 1250 and 9375 :-

9375=1250×7+625
1250=625×2+0
Since, remainder is 0, the H.C.F is 625
Now, H.C.F of (625,15625) is
15625=625×25+0

Hence 625 is the H.C.F of all the three numbers and divides 1251,9377 and 15628 leaving remainders 1,2 and 3, respectively.

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