Using graph paper, plot the points A(6,4) and B(0,4). (i) Reflect A and B in the origin to get the images A′ and B′. (ii) Write the co-ordinates of A′ and B′. (iii) State the geometrical name for the figures ABA′B′. (iv) Find its perimeter.
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Solution
(i) Please See Graph. (ii) Reflection of A' and B' in the origin=A′(−6,−4) and B′(0,−4) (iii) The geometrical name for the figure ABA'B' is a parallelogram. (iv) From the graph, AB=6cm, BB'=8cm. In ΔABB' (AB′)2=AB2+(BB′)2 =(6)2+(8)2=36+64=100 AB′=10=A′B (ABA'B' is a parallelogram) Perimeter of ABA'B'=A'B'+AB'+AB+A'B =6+10+6+10 =32 units.