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Question

Using graph paper, plot the points A(6,4) and B(0,4).
(i) Reflect A and B in the origin to get the images A and B.
(ii) Write the co-ordinates of A and B.
(iii) State the geometrical name for the figures ABAB.
(iv) Find its perimeter.

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Solution

(i) Please See Graph.
(ii) Reflection of A' and B' in the origin=A(6,4) and B(0,4)
(iii) The geometrical name for the figure ABA'B' is a parallelogram.
(iv) From the graph, AB=6cm, BB'=8cm.
In ΔABB'
(AB)2=AB2+(BB)2
=(6)2+(8)2=36+64=100
AB=10=AB (ABA'B' is a parallelogram)
Perimeter of ABA'B'=A'B'+AB'+AB+A'B
=6+10+6+10
=32 units.
615588_578787_ans_997bdc4d86e742718ae2bfbab88f533a.png

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