Using identities, evaluate:
$(1.02)^{2} - (0.98)^{2}$

Open in App

Solution

We have,
Let $a = 1.02$ and $b = 0.98$
$\begin{matrix} a^{2} - b^{2} = (a + b) (a - b) = (1.02 + 0.98) (1.02 - 0.98) = 2 (0.04) = 0.08 \end{matrix}$
Hence,
We get $0.08$

Suggest Corrections

Similar questions

(1.02)^{2} - (0.98)^{2}

Using $a^{2} - b^{2} = (a + b) (a - b)$ , find
${1.02}^{2} - {0.98}^{2}$

$(1.02)^{2} - (0.98)^{2} =$

Using a²-b²=(a+b)(a-b) find:

i. 51² - 49²

ii. (1.02)² - (0.98)²

Join BYJU'S Learning Program