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Question

Using identities, evaluate:
712.

A
5041
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B
3041
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C
6041
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D
2041
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Solution

The correct option is A 5041
Given, 712,
i.e. 712 =(70+1)2.

We know,
(x+y)2=x2+y2+2xy.

Then,
712=(70+1)2=702+(2×70×1)+12=4900+140+1=5040+1=5041.

Hence, 712=5041.

Therefore, option A is correct.

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