Question

Using identities, evaluate ${998}^2$

• A. $995704$
• B. $996004$
• C. $992004$
• D. $990004$

Answer 1

The correct option is B $996004$

${998}^2$
$=(1000-2{)}^2$
Using,
$(a-b{)}^2=a^2-2ab+b^2$ we get,
$=(1000{)}^2-2(1000\left)\right(2)+(2{)}^2$
$=1000000-4000+4$
$=996004$