Using identity (x−a)(x+a)=x2−a2,362−352=
In the Identity (x−a)(x+a)=x2−a2 We Put x=36 and a=35
(36-35)(36+35) = (1)(71)=71
Using a suitable identity, Solve 362−352
Using identity (x−a)(x+a)=x2−a2, find 62−52.