Question

Using integration find the area of region bounded by the triangle whose vertices are (-1, 0),(1, 3) and (3, 2).

Answer 1

For equations of AB, BC & AC

$Area={\int }_1^{-1}{y}_{BC}dx+{\int }_3^1{y}_{BC}dx-{\int }_3^{-1}{y}_{AC}dx$

= 4 sq. units