MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Intercept Form of a Line

Using integra...

Question

Using integration, find the area of the triangle formed by negative $x - a x i s$ and tangent and normal to the circle $x^{2} + y^{2} = 9$ at $(- 1, 2 \sqrt{2})$ .

Open in App

Solution

Therefore, Area of triangle = 9√5/4 units^2.

Suggest Corrections

thumbs-up

0

Similar questions

Q. The area of the triangle formed by the positive

x

-axis and the normal and tangent to the circle

x^{2} + y^{2} = 4

(1, \sqrt{3})

Q. The area of triangle formed by the tangent, normal drawn at

(1, \sqrt{3})

x^{2} + y^{2} = 4

and positive x-axis is

Q. The area of the triangle formed by the positive x-axis and the normal and the tangent to the circle

x^{2} + y^{2} = 4

(1, \sqrt{3})

Q. Area of the triangle formed by the tangent and normal at the point

(1, \sqrt{3})

x^{2} + y^{2} = 4

and with positive

x

Q. Show that the area of the triangle formed by the positive x-axis and the normal and the tangent to the circle

x^{2} + y^{2} = 4

(1, \sqrt{3})

2 \sqrt{3}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Straight Line

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Intercept Form of a Line

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon