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Question

Using L'Hospital's Rule, evaluate:
limxπ2xtanxπ4secx

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Solution

limxπ2xtanxπ4secx

limxπ2xsinxcosxπ41cosx

limxπ24xsinxπ4cosx

limxπ24(xcosx+sinx)4sinx

=π2×0+11

=11

=1


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