Question

Using laws of exponents , simplify and write the answer in exponential form:

${\left(4^3\right)}^4÷{\left(4^2\right)}^6$

Answer 1

Given,

$$\begin{gathered} {\left(4^3\right)}^4÷{\left(4^2\right)}^6 \\ =4^{3\times 4}\times 4^{-\left(2\times 6\right)} \\ =4^{12}\times 4^{-12} \\ ={\left(4\right)}^{12-12} \\ ={\left(4\right)}^0 \\ =1 \end{gathered}$$ …[ Using exponent law : ${\left(a^n\right)}^m=a^{mn}$ and $a^n\times b^n={\left(a\times b\right)}^n$ ]

Hence, required value is $1$ .