Question

Using $\log 2=0.3010$ and $\log 3=0.4771$ and $\log 7=0.8451$ find the value of $\log 6^{50}$

Answer 1

$\log 6^{50}=50\log 6$

$=50(\log 2+\log 3)$

$=50(0.3010+0.4771)$

$=50\times 0.7781=38.905$