Question

Using logarithm, find the value of $6.45\times 981.4$

Answer 1

Let $x=6.45\times 981.4$.

Taking log on both sides
$\log x=\log (6.45\times 981.4)$
$=\log 6.45+\log 981.4$
$=0.8096+2.9919$ (using log table)
$=3.8015$
$\therefore x=antilog\left(3.8015\right)=6331.0$ (using antilog table)

Ans: 6331