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Dimensional Analysis

Using mass ...

Question

Using mass $(M)$ , length $(L)$ , time $(T)$ and current $(A)$ as fundamental quantities, the dimensions of permeability are

[M^{- 1} L T^{- 2} A]

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[M^{- 2} L T^{- 2} A^{- 1}]

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[M L T^{- 2} A^{- 2}]

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[M L T^{- 1} A^{- 1}]

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Solution

The correct option is D $[M L T^{- 2} A^{- 2}]$

$B = μ n i; F = B q v$

$F = μ n i q v \Rightarrow μ = \frac{F}{n i q v}$

$μ = \frac{M L T^{- 2}}{\frac{1}{L} A . A T . L T^{- 1}}$ [n is no. of turns per unit length]

$= M L A^{- 2} T^{- 2}$

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Similar questions

e

m

c

h

μ_{0}

[h] = [M L^{2} T^{- 1}], [μ_{0}] = [M L T^{- 2} A^{- 2}]

e

m

c

h

μ_{0}

[h] = [M L^{2} T^{- 1}], [μ_{0}] = [M L T^{- 2} A^{- 2}]

(M)

(L)

(T)

(A)

[M L T^{- 1}]

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