The correct options are
B 100l9m2
C 100l6m2
To find the L.C.M. of two or more monomials is the product of the L.C.M. of their numerical coefficients and the L.C.M. of their literal coefficients.
The L.C.M. of numerical coefficients = The L.C.M. of 50 and 100.
50=2×25
100=2×2×25
Therefore, L.C.M. of 50 and 100=2×2×25=100
The L.C.M. of literal coefficients = The L.C.M. of l6m2,l3=l6m2
So, the L.C.M. of 100l6m2,50l3=100l6m2