Using prime factorization , find the HCF and LCM of $144, 198$
in each case , verify that $H C F \times L C M$ = product of given numbers.

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Solution

$144 = 2^{4} \times 3^{2}$
$198 = 2 \times 3^{2} \times 11$
LCM (144, 198 ) = $2^{4} \times 3^{2} \times 11 = 1584$
HCF ( 144, 198 ) = $2 \times 3^{2} = 18$
verification :
$H C F \times L C = 1518 \times 18 = 28512$
Product of given numbers = $144 \times 198 = 28512$
$\Rightarrow H C F \times L C M =$ product of given numbers.
verified.

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Using prime factorization , find the HCF and LCM of 144,198 in each case , verify that HCF×LCM = product of given numbers.

144=24×32198=2×32×11LCM (144, 198 ) = 24×32×11=1584HCF ( 144, 198 ) = 2×32=18verification :HCF×LC=1518×18=28512Product of given numbers = 144×198=28512⇒HCF×LCM= product of given numbers.verified.

Using prime factorization , find the HCF and LCM of $144, 198$
in each case , verify that $H C F \times L C M$ = product of given numbers.