Using prime factorization method, find the HCF of $144, 180$ and $192$

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Solution

Finding HCF of $144, 180$ and $192$
Prime Factors of $144 = 2 \times 2 \times 2 \times 2 \times 3 \times 3$
Prime Factors of $180 = 2 \times 2 \times 3 \times 3 \times 5$
Prime Factors of $192 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3$
Common Factors of $144, 180$ and $192$ are $2, 2,$ and $3$
Hence, the HCF of $144, 180$ and $192$ is $2 \times 2 \times 3 = 12$

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