Using prime factorization method, find the HCF of $40, 48$ and $72$

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Solution

Finding HCF of $40, 48$ and $72$
Prime Factors of $40 = 2 \times 2 \times 2 \times 5$
Prime Factors of $48 = 2 \times 2 \times 2 \times 2 \times 3$
Prime Factors of $72 = 2 \times 2 \times 2 \times 3 \times 3$
Common Factors of $40, 48$ and $72$ are $2, 2,$ and $2$
Hence, the HCF of $40, 48$ and $72$ is $2 \times 2 \times 2 = 8$

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