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Question

Using principal values, evaluate the following
cos1(cos2π3)+ sin1(sin2π3)

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Solution

cos1(cos2π3)+sin1(sin2π3)
Figure 1 represents graph of sin1sinx
Figure 2 represents graph of cos1cosx
Hence, cos1cos2π3+sin1sin2π3
=2π3+π2π3
=2π3+π3=π



1016966_1018950_ans_b4224ab6349a4a838d35e961b9ee45b5.png

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