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Question

Using properties of determinants, prove the following:
∣ ∣ ∣a2bcac+c2a2+abb2acabb2+bcc2∣ ∣ ∣=4a2b2c2.

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Solution

∣ ∣ ∣a2bcac+c2a2+abb2acabb2+bcc2∣ ∣ ∣.
Adding row 2 and row 3 to row 1 and taking out common factor, we get:
2∣ ∣ ∣a2+abb2+bcac+c2a2+abb2acabb2+bcc2∣ ∣ ∣
Subtracting row 3 from row 1, we get:
2∣ ∣ ∣a20aca2+abb2acabb2+bcc2∣ ∣ ∣
Subtracting row 1 from row 2, we get:
2∣ ∣ ∣a20acabb20abb2+bcc2∣ ∣ ∣
Subtracting row 2 from row 3, we get:
2∣ ∣ ∣a20acabb200bcc2∣ ∣ ∣
the above determinant on expansion gives:
2a2b2c2+2ac.ab.bc=4a2b2c2.

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