CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
423
You visited us 423 times! Enjoying our articles? Unlock Full Access!
Question

Using properties of determinants, prove the following:
∣ ∣ ∣a2bcac+c2a2+abb2acabb2+bcc2∣ ∣ ∣=4a2b2c2.

Open in App
Solution

∣ ∣ ∣a2bcac+c2a2+abb2acabb2+bcc2∣ ∣ ∣.
Adding row 2 and row 3 to row 1 and taking out common factor, we get:
2∣ ∣ ∣a2+abb2+bcac+c2a2+abb2acabb2+bcc2∣ ∣ ∣
Subtracting row 3 from row 1, we get:
2∣ ∣ ∣a20aca2+abb2acabb2+bcc2∣ ∣ ∣
Subtracting row 1 from row 2, we get:
2∣ ∣ ∣a20acabb20abb2+bcc2∣ ∣ ∣
Subtracting row 2 from row 3, we get:
2∣ ∣ ∣a20acabb200bcc2∣ ∣ ∣
the above determinant on expansion gives:
2a2b2c2+2ac.ab.bc=4a2b2c2.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon