Step: Solve for x
If ab=cd then a+ba−b=c+dc−d
Given, 3x+√9x2−53x−√9x2−5=5
⇒3x+√9x2−5+3x−√9x2−53x+√9x2−5−3x+√9x2−5=5+15−1
⇒6x2√9x2−5=64
⇒x√9x2−5=12
Squaring both sides, we get
⇒x29x2−5=14
⇒9x2−5=4x2
[cross multiplication]
⇒9x2−4x2=5
⇒5x2=5
⇒x2=1
⇒x=1 or −1
Hence, the value of x is 1 or −1.