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Question

Using property of proportion solve for X

(1+x+x^2)/(1-x+x^2)= 49(1+X)/63(1-x)

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Solution

(1+x+x²)/(1-x+x²) = 49(1+x)/63(1-x)

⇒63(1-x)(1+x+x²) = 49(1+x)(1-x+x²)
⇒63[1+x+x²-x-x²-x³] =49 [ 1-x+x² +x-x²+x³]
⇒63[1-x³]= 49[1+x³]
⇒63-63x³ =49 +49x³
⇒63-49 =49x³+63x³
⇒14= 112x³
112/14x³ =1
8x³ =1
x³=1/8
​​​​​

x³ =(1/2)³
∴x=1/2


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