Using quadratic formula, factorize the equation : [3 MARK]
$5 x^{2} - 10 x + 3 = 0$

Open in App

Solution

Formula : 1 Mark
Roots : 1 Mark
Factorisation : 1 Mark

Given equation is,

$5 x^{2} - 10 x + 3 = 0$

$\Rightarrow a = 5, b = - 10, c = 3$

D = $b^{2} - 4 a c = (- 10)^{2} - 4 * 5 * 3 = 40$

Roots = $\frac{- b \pm \sqrt{D}}{2 a}$ = $\frac{10 \pm \sqrt{4} 0}{2 * 5}$

$∴$ The roots are 0.367 and 1.632 (approximately)

So, factorising the given equation:
$\Rightarrow (x - 0.367) (x - 1.632) = 0$

Suggest Corrections

Similar questions

\sqrt{3} x^{2} + 10 x + 7 \sqrt{3} = 0

3 x^{2} = - 10 x - 5

Using quadratic formula solve the following quadratic equation: [3 MARKS]

$p^{2} x^{2} + (p^{2} - q^{2}) x - q^{2} = 0, p \neq 0$

\sqrt{3} x^{2} + 10 x - 8 \sqrt{3} = 0

9 x^{2} - 9 (a + b) x + (2 a^{2} + 5 a b + 2 b^{2}) = 0

Join BYJU'S Learning Program