Question

Using quadratic formula find the roots of the quadratic equation $2x^2-7x+3=0$ .

• A. $x=\frac{3}{2}$
• B. $x=\frac{1}{2}$
• C. $x=3$
• D. $x=-3$

Answer 1

Answer: (B), (C)

The correct options are
B

$x=\frac{1}{2}$

C

$x=3$

$2x^2-7x+3=0$
On comparing this equation with $a{x}^2+bx+c=0$, we get
a = 2, b = -7 and c = 3
By using quadratic formula, we get,
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
$\Rightarrow$ $x=\frac{-(-7)\pm \sqrt{(-7{)}^2-4\times 2\times 3}}{2\times 2}$
$\Rightarrow$ $x=\frac{7\pm \sqrt{2}5}{4}$
$\Rightarrow x=\frac{7\pm 5}{4}$
$\Rightarrow x=\frac{7+5}{4}orx=\frac{7-5}{4}$
$\Rightarrow x=\frac{12}{4}or\frac{2}{4}$
$\therefore x=3or\frac{1}{2}$