Using rearagement property find the sum 4/3+3/5+-2/3+-11/5

Open in App

Solution

Dear student

$\frac{4}{3} + \frac{3}{5} + (- \frac{2}{3}) + (- \frac{11}{5}) = [\frac{4}{3} + (- \frac{2}{3})] + [\frac{3}{5} + (- \frac{11}{5})] [Rearranging] = [\frac{4 - 2}{3}] + [\frac{3 - 11}{5}] = \frac{2}{3} + (- \frac{8}{5}) = \frac{10 - 24}{15} = - \frac{14}{15}$
Regards

Suggest Corrections

Similar questions

- \frac{7}{11} \times \frac{- 3}{5} = \frac{- 3}{5} \times \frac{- 7}{11}

Find the following by using appropriate property

3/5×(-2/5)+5/2(-3/5)×1/6

Use the distributive property and calculate : $\frac{11}{37} (\frac{5}{11} + \frac{2}{3})$

\frac{- 2}{3} \times \frac{3}{5} + \frac{5}{2} - \frac{3}{5} \times \frac{1}{6}

Join BYJU'S Learning Program