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Question

Using remainder theorem, find the remainder when:
(2x3 − 5x2 + 9x − 8) is divided by (x − 3)

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Solution

We have:
x-3=0x=3
By the remainder theorem, we know that when f(x) is divided by (x - 3), the remainder is f(3).
Thus, we have:
fx=2x3-5x2+9x-8 f3=2×33-5×32+9×3-8 =54-45+27-8 =28
​Hence, the required remainder is 28.

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