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Question

Using remainder theorem, find the remainder when:
(2x4 + 6x3 + 2x2 + x − 8) is divided by (x + 3)

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Solution

We have:
x+3=0x=-3
By the remainder theorem, we know that when f(x) is divided by (x + 3), the remainder is f(-3).
Thus, we have:
fx=2x4+6x3+2x2+x-8 f-3=2×-34+6×-33+2×-32+-3-8 =162-162+18-11 =7
​Hence, the required remainder is 7.

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