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Question

Using remainder theorem, find the reminder when $$4x^3+5x-10$$ is divided by $$x-3$$


A
12
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B
18
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C
96
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D
113
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Solution

The correct option is D $$113$$
Let $$p(x)=4x^3+5x-10$$ and    
 $$g(x)=x-3$$   
 $$=>x-3=0$$   
 $$=>x=3$$
The remainder when $$p(x)$$ is divided by $$g(x)$$ is $$p(3)$$ (By Remainder Theorem)
Thus, $$p(3)=4(3)^3+5(3)-10$$                     
                  $$=108+15-10$$                     
                   $$=113$$
Therefore,
Remainder=$$113$$

Mathematics

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