Question

Using ruler and compass only, construct the quadrilateral ABCD, having given AB = $5$ cm, BC = $2.5$ cm, CD = $6$ cm, angle BAD = ${90}^{\circ }$ and the diagonal AC = $5.5$ cm.

Answer 1

Steps :
(i) draw AB = 5 cm.
(ii) Now draw $\angle XAB$ such that it is ${90}^{\circ }$.
(iii) taking A and B as a ceentre and radus 2.5 cm and 5.5 cm draw arcs cuts off at C.
(iv) Now join BC and AC.
(v) Taking C as a centre and radius 6 cm draw arcs at D on AX.
ABCD is the required quadriateral.