Question

Using ruler and compasses only, construct a parallelogram ABCD, in which : AB = 6 cm, AD = 3 cm and $\angle DAB={60}^{\circ }$. In the same figure draw the bisector of angle DAB and let it meet DC at point P. Measure angle APB.

Answer 1

Steps :

1. Draw AB = 6 cm

2. At A draw $\angle QAB={60}^{\circ }$.

3. From AQ cut AD = 3 cm.

4. From D, draw an arc of radius 6 cm.

5. From B, draw an arc of radius 3 cm which meets first arc at C.

6. Join CD and BC.

Thus ABCD is the required || gm.

7. Bisect $\angle DAB$, so that bisector meets CD at P.

8. Join PB and measure $\angle APB$.

$\therefore \angle APB={90}^{\circ }$.