Question

Using standard identity, find the value of ${102}^2$.

• A. $10402$
• B. $10408$
• C. $10204$
• D. $10404$

Answer 1

The correct option is D $10404$

Given, ${102}^2$

$=(100+2{)}^2$.

We know, $(a+b{)}^2=a^2+2ab+b^2$.

Then,

${102}^2$

$=(100+2{)}^2$

$={100}^2+2^2+2\left(2\right)\left(100\right)$

$=10000+4+400$

$=10404$.

Therefore, option $D$ is correct.